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Author Topic: From another Board/You gotta see this  (Read 3673 times)

Lori

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From another Board/You gotta see this
« on: January 18, 2011, 12:29:39 PM »
This year we will experience 4 unusual dates.... 1/1/11, 1/11/11, 11/1/11, 11/11/11 ......... NOW go figure this out.... take the last 2 digits of the year you were born plus the age you will be this year and it WILL EQUAL .... 111

   64
+ 47
 111


Jimfarmer

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Re: From another Board/You gotta see this
« Reply #1 on: January 18, 2011, 03:32:07 PM »
"take the last 2 digits of the year you were born plus the age you will be this year and it WILL EQUAL .... 111" 

Not a coincidence that 111 should occur in 2011, nor that everybody should get the same result.

Here are the results that you will/did get in some other years:
2009:   09 or109 .  Examples:  Born in 2001, so 01+8 = 09.   Born in 1991, so 91+ 18 = 109.
2010:  10 or 110.   Examples:  Born in 2001, so 01+9 = 10.   Born in 1991, so 91+ 19 = 110.
2011:  11 or 111.  Examples:  Born in 2001, so 01+10 = 11.   Born in 1991, so 91+ 20 = 111.
2012:  12 or 112.   Examples:  Born in 2001, so 01+11 = 12.   Born in 1991, so 91+ 21 = 112.
2013:  13 or 113.   Examples:  Born in 2001, so 01+12 = 13.   Born in 1991, so 91+ 22 = 113.

Here is the mechanism:  If you were born in year 19xx or 20xx, then in that year you completed 0 years, and xx+0=xx.  Then the next year, you completed 1 year of age, so xx+1=xx+1.  Then the following year, you completed 2 years, so xx+2=xx+2.  Etc.  In general, xx+N=xx+N.  In other words, with each successive year, both the year number and your age increase by 1, thus keeping "in step".

EDIT:  I did not explain that well;  I'll try again.
If you were born in year yyxx,  where yy is either 19 or 20,  then N years later, the year is yyxx+N and your age is N.  So, the last two digits of the current year is xx+N;  and the last two digits of your birth year plus your age is also xx+N.  Now, someone born M years after you were born was born in year yyxx+M, and at that time his age was zero, so the last two digits of his birth year plus his age was xx+M+0, or just xx+M, which is, of course, equal to the last two digits of the current year at that time.  Now, at year yyxx+N,  the number of years elapsed since year yyxx+M -- when the younger person was born -- is N-M; and so his age is exactly N-M also.   What will that younger person calculate for the sum of the last two digits of his birth year plus his age?  This:  (xx+M)+(N-M), which equals xx+N, which is the same number that you calculate for the last two digits of your birth year plus your age. 
« Last Edit: January 19, 2011, 03:09:31 AM by Jimfarmer »

Ed Douglas

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Re: From another Board/You gotta see this
« Reply #2 on: January 18, 2011, 06:11:20 PM »
Except the fact that Pi is infinite.  ed

 

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